2025100 marks25 questions
24 of its 25 questions are here. The rest have a figure or are still being checked, so for now they're only in the official PDF.
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Source: JEE (Main) 2025, Paper 1 (B.E./B.Tech), 7 Apr 2025 Shift 1, Maths, published by NTA. The official PDF
If for θ ∈ [−π/3, 0], the points (x, y) = (3 tan(θ + π/3), 2 tan(θ + π/6)) lie on xy + αx + βy + γ = 0, then α² + β² + γ² is equal to
Among the statements (S1) : The set {z ∈ C − {−i} : |z| = 1 and (z − i)/(z + i) is purely real} contains exactly two elements, and (S2) : The set {z ∈ C − {−1} : |z| = 1 and (z − 1)/(z + 1) is purely imaginary} contains infinitely many elements.
Let the set of all values of p ∈ R, for which both the roots of the equation x² − (p + 2)x + (2p + 9) = 0 are negative real numbers, be the interval (α, β]. Then β − 2α is equal to
Let the system of equations: 2x + 3y + 5z = 9, 7x + 3y − 2z = 8, 12x + 3y − (4 + λ)z = 16 − μ, have infinitely many solutions. Then the radius of the circle centred at (λ, μ) and touching the line 4x = 3y is
Let A be a 3 × 3 matrix such that |adj (adj (adj A))| = 81. If S = {n ∈ Z : (|adj (adj A)|)^((n−1)²/2) = |A|^(3n²−5n−4)}, then ∑ₙ∈S |A^(n²+n)| is equal to
Let x₁, x₂, x₃, x₄ be in a geometric progression. If 2, 7, 9, 5 are subtracted respectively from x₁, x₂, x₃, x₄, then the resulting numbers are in an arithmetic progression. Then the value of 1/24 (x₁ x₂ x₃ x₄) is:
The remainder when ((64)⁶⁴)⁶⁴ is divided by 7 is equal to
From a group of 7 batsmen and 6 bowlers, 10 players are to be chosen for a team, which should include atleast 4 batsmen and atleast 4 bowlers. One batsmen and one bowler who are captain and vice-captain respectively of the team should be included. Then the total number of ways such a selection can be made, is