2025100 marks25 questions
18 of its 25 questions are here. The rest have a figure or are still being checked, so for now they're only in the official PDF.
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Source: JEE (Main) 2025, Paper 1 (B.E./B.Tech), 8 Apr 2025 Shift 2, Physics, published by NTA. The official PDF
A quantity Q is formulated as x⁻²y³⁄²z⁻²⁄⁵. X, Y and Z are independent parameters which have fractional errors of 0.1, 0.2 and 0.5, respectively in measurement. The maximum fractional error of Q is
A body of mass 2 kg moving with velocity of v⃗ᵢₙ = 3î + 4ĵ ms⁻¹ enters into a constant force field of 6N directed along positive z-axis. If the body remains in the field for a period of 5/3 seconds, then velocity of the body when it emerges from force field is.
A rod of linear mass density ‘λ’ and length ‘L’ is bent to form a ring of radius ‘R’. Moment of inertia of ring about any of its diameter is.
Two balls with same mass and initial velocity, are projected at different angles in such a way that maximum height reached by first ball is 8 times higher than that of the second ball. T₁ and T₂ are the total flying times of first and second ball, respectively, then the ratio of T₁ and T₂ is
A 3 m long wire of radius 3 mm shows an extension of 0.1 mm when loaded vertically by a mass of 50 kg in an experiment to determine Young's modulus. The value of Young's modulus of the wire as per this experiment is P × 10¹¹ Nm⁻², where the value of P is: (Take g = 3π m/s²)
Water falls from a height of 200 m into a pool. Calculate the rise in temperature of the water assuming no heat dissipation from the water in the pool. (Take g = 10 m/s², specific heat of water = 4200 J/(kg K))
A monoatomic gas having γ = 5/3 is stored in a thermally insulated container and the gas is suddenly compressed to (1/8)ᵗʰ of its initial volume. The ratio of final pressure and initial pressure is: (γ is the ratio of specific heats of the gas at constant pressure and at constant volume)
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R Assertion A : Work done in moving a test charge between two points inside a uniformly charged spherical shell is zero, no matter which path is chosen. Reason R : Electrostatic potential inside a uniformly charged spherical shell is constant and is same as that on the surface of the shell. In the light of the above statements, choose the correct answer from the options given below